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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Let the minimum value v0v_0 of v=∣z∣2+∣z−3∣2+∣z−v=|z|^2+|z-3|^2+\mid z- 6i∣2,z∈C\left.6 i\right|^2, \quad z \in \mathbb{C} is attained at z=z0z=z_0. Then ∣2z02−zˉ03+3∣2+v02\left|2 z_0^2-\bar{z}_0^3+3\right|^2+v_0^2 is equal to
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Correct option: A
1000
Option A (1000) is correct because by finding the minimum value of v and the corresponding z_0, we can substitute these values into the given expression and evaluate it to 1000.

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