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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Analyzing +4 | -1
(A): A→B,ΔH=+ve,ΔS=+veA \rightarrow B, \Delta H=+v e, \Delta S=+v e, ΔG=−ve\Delta G=-v e at low temperature.

(R) : −TΔS>ΔH-T \Delta S > \Delta H at low temperature.
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Correct option: A
AA and RR are true, RR explains AA
Option D (AA and RR are true, RR explains AA) is correct because at low temperatures, the -TΔS term is smaller, making ΔG positive unless -TΔS is greater than ΔH.

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