JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Understanding +4 | -1

The interval for which

\sin ^{-1} \sqrt{x}+\cos ^{-1} \sqrt{x}=\frac{\pi}{2}

holds

View answer and explanation

Correct option: C

[0,1]

Option C (

[0, 1]

) is correct because the identity

\sin^{-1}(x) + \cos^{-1}(x) = \frac{{\pi}}{{2}}

holds for all

x

in the interval [-1, 1], but since we have

\sqrt{x}

x

must be non-negative, and

\sqrt{x}

must be in [-1, 1], which means

x

is in [0, 1].

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