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JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

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The value of k so that x2+y2+kx+4y+2=0{x^2} + {y^2} + kx + 4y + 2 = 0 and 2(x2+y2)−4x−3y+k=02\left( {{x^2} + {y^2}} \right) - 4x - 3y + k = 0 cut orthogonally, is
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Correct option: C
−103- \frac{{10}}{3}
Option C (−103- \frac{{10}}{3}) is correct because it is the value of k that satisfies the condition for two circles to cut orthogonally.

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