JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \frac{\cos x-\sin x}{1+\sin 2 x} d x=

View answer and explanation

Correct option: A

-\frac{1}{\cos x+\sin x}+c

Option A is correct because the integral simplifies to

-\frac{1}{\cos x + \sin x} + c

after recognizing the denominator as

(\sin x + \cos x)^2

and using substitution.

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