Question

The function $f\left( x \right) = \log \left( {\frac{{1 + x}}{{1 - x}}} \right)$ satisfies the equation

Accepted Answer

$f\left( x \right) + f\left( y \right) = f\left( {\frac{{x + y}}{{1 + xy}}} \right)$

Answer

$f\left( {x + 2} \right) - 2f\left( {x + 1} \right) + f\left( x \right) = 0$

Answer

$f\left( x \right) + f\left( {x + 1} \right) = f\left\{ {x\left( {x + 1} \right)} \right\}$

Answer

$f\left( {x + y} \right) = f\left( x \right)f\left( y \right)$

JEE MATHEMATICS MCQ: FUNCTIONS

More Questions from FUNCTIONS