JEE PHYSICS MCQ: THERMODYNAMICS

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A carnot engine, having efficiency of

\eta = \frac{1}{{20}}

as heat engine, is used as a refrigerator. If the work done on the system is 20 J, the amount of energy absorbed from the reservoir at lower temperature is

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Correct option: D

380 J

Option D (380 J) is correct because it represents the heat extracted from the cold reservoir when the Carnot engine operates as a refrigerator.

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The work done in which of the following process is zero? Water is used to cool the radiators of engines in cars because A gas expand

0.25\,\,{m^3}

at constant pressure

{10^3}N/{m^2},

the work done is A thermodynamic process in which temperature

T

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P

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V

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\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)