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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1
The amplitude of a damped oscillator varies with time as A(t)=A0exp⁡(−bt/2m)A(t)={A}_0 \exp (-b t / 2 m) where b=b= 70 g/s70 \mathrm{~g} / \mathrm{s} and m=200 gm=200 \mathrm{~g}. How long does it take for the mechanical energy to drop to one - fourth of its initial value? [Take ln 2 = 0.7]
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Correct option: B
4.0 s4.0 \mathrm{~s}
Option B (4.0 s4.0 \mathrm{~s}) is correct because it's calculated by finding the time it takes for the mechanical energy of a damped oscillator to drop to one-fourth of its initial value using the given parameters.

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