JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

The equation of the tangent to the curve

x = t\cos t,\;y = t\sin t

at the origin is

View answer and explanation

Correct option: B

y = 0

Option B (

y = 0

) is correct because at the origin (t=0), the slope

\frac{{dy}}{{dx}}

is 0, indicating a horizontal tangent.

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z