JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Medium

1 of 1

Application +4 | -1

The point on the curve

y = 2{x^2} - 6x - 4

at which the tangent is parallel to the

x

-axis, is

View answer and explanation

Correct option: D

\left( {\frac{3}{2},\; - \frac{{17}}{2}} \right)

Option D ((

\frac{3}{2}

,\\; -

\frac{{17}}{2}

)) is correct because it represents the point on the curve where the derivative (slope of the tangent) is zero, indicating a horizontal tangent.

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z