JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

f:R \to R\;and\;g:R \to R

are defined by

f\left( x \right) = \left| x \right|\;and\;g\left( x \right) = \left[ {x - 3} \right]

for

x \in R

, then

\left\{ {g\left( {f\left( x \right)} \right): - \frac{8}{5} < x < \frac{8}{5}} \right\}

is equal to

View answer and explanation

Correct option: C

\left\{ { - 3,\mathrm{ } - 2} \right\}

Option C (

\left\{ { - 3,\; - 2} \right\}

) is correct because it represents the set of values obtained by evaluating g(f(x)) for the given range of x.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}