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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫1cos⁡−1x⋅1−x2dx=\int \frac{1}{\cos ^{-1} x \cdot \sqrt{1-x^2}} d x=
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Correct option: B
−log⁡(cos⁡−1x)+c-\log \left(\cos ^{-1} x\right)+c
Option B (−log⁡(cos⁡−1x)+c-\log \left(\cos ^{-1} x\right)+c) is correct because the integral simplifies to this form after a u-substitution.

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