JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

f\left( x \right) = \frac{{{{\sin }^4}x + {{\cos }^2}x}}{{{{\sin }^2}x\; + {{\cos }^4}x}}

for

x \in R,

then

f\left( {2010} \right) =

View answer and explanation

Correct option: A

Option A (1) is correct because the function simplifies to 1 for all real values of x due to trigonometric identities.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f\left( x \right) = x - \left[ x \right]

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S=\left\{x: f(x)=f^{-1}(x)\right\}