JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

Let

f=\left\{\left(x, \frac{x^2}{1+x^2}\right): x \in R\right\}

be a function from

R

into

R

. The range of

f

View answer and explanation

Correct option: C

[0,1)

Option C (

[0,1)

) is the correct answer because the range of the function

f(x)=\frac{{x^2}}{{1+x^2}}

is all values greater than or equal to 0 and strictly less than 1.

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