Eq.wt. of ${\rm{N}}{{\rm{H}}_3}$ in, ${\rm{N}}{{\rm{H}}_3} + {{\rm{O}}_2} \to {\rm{NO}} + {{\rm{H}}_2}{\rm{O}}$ is :

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

1 Easy

1 of 1

Application +4 | -1

Eq.wt. of

\mathrm{N}{\mathrm{H}_3}

in,

\mathrm{N}{\mathrm{H}_3} + {\mathrm{O}_2} \to \mathrm{NO} + {\mathrm{H}_2}\mathrm{O}

is :

View answer and explanation

Correct option: A

3.4

Option A (3.4) is correct because the equivalent weight is calculated by dividing the molecular weight by the change in oxidation number.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }