JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium

1 of 1

Analyzing +4 | -1

The range of the function

f(x)=\frac{\sin \left(\pi\left[x^2+1\right]\right)}{x^4+1}

where, [] is greatest integer function, is

View answer and explanation

Correct option: C

\{0\}

Option C (

\{0\}

) is correct because the numerator

\sin(\pi[x^2+1])

is always 0, making the entire function equal to 0.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}