JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

For all complex numbers

\mathrm{z}

of the form

1+\mathrm{i} \alpha, \alpha \in \mathrm{R}

, if

\mathrm{z}^{2}=\mathrm{x}+\mathrm{iy}

, then

View answer and explanation

Correct option: B

y^{2}+4 \mathrm{x}-4=0

Option B (y² + 4x - 4 = 0) is correct because substituting z = 1 + iα into z² = x + iy and eliminating α results in the equation y² + 4x - 4 = 0.

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