Question

If $x+y-z+x y z=0$, then $\frac{2 x}{1-x^2}+\frac{2 y}{1-y^2}-\frac{2 z}{1-z^2}$ is equal to

Accepted Answer

$\frac{8 x y z}{\left[\left(1-x^2\right)\left(1-y^2\right)\left(1-z^2\right)\right]}$

Answer

$\frac{x y z}{\left[\left(1-x^2\right)\left(1-y^2\right)\left(1-z^2\right)\right]}$

Answer

$\frac{-x y z}{\left[\left(1-x^2\right)\left(1-y^2\right)\left(1-z^2\right)\right]}$

Answer

$\frac{-8 x y z}{\left[\left(1-x^2\right)\left(1-y^2\right)\left(1-z^2\right)\right]}$

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

More Questions from TRIGONOMETRY RATIOS