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JEE PHYSICS MCQ: THERMODYNAMICS

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Understanding +4 | -1
(A): CpC_p is always greater than CVC_V in gases.
(R): Work done at constant pressure is more than at constant volume.
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Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because CpC_p is always greater than CVC_V for gases, and the reason correctly explains this: work done at constant pressure is more than at constant volume, requiring more heat input.

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