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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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1−c2=nc−1\sqrt{1-c^2}=n c-1 and z=eiθz=e^{i \theta}, then c2n(1+nz)(1+nz)\frac{c}{2 n}(1+n z)\left(1+\frac{n}{z}\right) is equal to
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Correct option: C
1+c cosθ1+c \ cos \theta
Option C (1+ccos⁡θ1+c \cos \theta) is the correct answer because after simplification and using the given equation, the expression reduces to 1+ccos⁡θ1+c \cos \theta.

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