Through the point $ (13,31) $ a straight line is drawn to meet the axes of $ X $ and $ Y $ at $ Q $ and $ S $ respectively. If the rectangle $OQRS$ is completed, the co-ordinates of $ {R} $ satisfy the equation.

$ \frac{31}{x}+\frac{13}{y}=1 $

$ \frac{31}{x}-\frac{13}{y}=1 $

JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Application +4 | -1

Through the point

(13,31)

a straight line is drawn to meet the axes of

X

and

Y

Q

and

S

respectively. If the rectangle

OQRS

is completed, the co-ordinates of

{R}

satisfy the equation.

View answer and explanation

Correct option: A

\frac{13}{x}+\frac{31}{y}=1

Option A (

\frac{13}{x}

\frac{31}{y}

=1) is correct because it represents the equation satisfied by the coordinates of point R, derived from the given geometric conditions.