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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1

A square plate

0.15 \mathrm{~m}

side moves parallel to second plate with a velocity of

0.1 \mathrm{~ms}^{-1}

both plates being immersed in water. If the viscous force is

0.0025 \mathrm{~N}

and the coefficient of viscosity 0.001 poise, distance between the plates is:

View answer and explanation

Correct option: C

0.0009 m

Option C (0.0009 m) is correct because it is calculated by using the formula for viscous force,

F = \eta A \frac{dv}{dx}

, and solving for the distance

dx

.

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