Calculate the emf of the cell ${\rm{Cu}}\left( s \right)\left| {{\rm{C}}{{\rm{u}}^{2 + }}\left( {aq} \right)} \right|\left| {{\rm{A}}{{\rm{g}}^ + }\left( {aq} \right)} \right|{\rm{Ag}}\left( s \right)$ Given, $E_{{\rm{C}}{{\rm{u}}^{2 + }}/{\rm{cu}}}^ \circ = + 0.34V,E_{{\rm{A}}{{\rm{g}}^ + }/{\rm{Ag}}}^ \circ = 0.80V$ ,

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Application +4 | -1

Calculate the emf of the cell

\mathrm{Cu}\left( s \right)\left| {\mathrm{C}{\mathrm{u}^{2 + }}\left( {aq} \right)} \right|\left| {\mathrm{A}{\mathrm{g}^ + }\left( {aq} \right)} \right|\mathrm{Ag}\left( s \right)

Given,

E_{\mathrm{C}{\mathrm{u}^{2 + }}/\mathrm{cu}}^ \circ = + 0.34V,E_{\mathrm{A}{\mathrm{g}^ + }/\mathrm{Ag}}^ \circ = 0.80V

View answer and explanation

Correct option: A

+0.46 V

Option A (+0.46 V) is correct because it is the calculated EMF of the cell using the given standard reduction potentials.