JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Analyzing +4 | -1

In van der Wall equation

\left[P+\frac{a}{V^2}\right][V-b]=R T ; P

is pressure,

V

is volume,

R

is universal gas constant and

T

is temperature. The ratio of constants

\frac{a}{b}

is dimensionally equal to:

View answer and explanation

Correct option: C

P V

The correct answer is C (

P V

) because dimensional analysis of the van der Waals equation reveals that a/b has the same dimensions as PV.

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