JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

Let

I(x)=\int \frac{6}{\sin ^2 x(1-\cot x)^2} d x

. If

I(0)=3

, then

{I}\left(\frac{\pi}{12}\right)

is equal to :

View answer and explanation

Correct option: B

3 \sqrt{3}

Option D (

3 \sqrt{3}

) is correct because after evaluating the integral and applying the given initial condition, we find the value of

I(\frac{\pi}{12})

to be

3\sqrt{3}

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