JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Analyzing +4 | -1

\int\left(x+\sqrt{1+x^2}\right)^n d x.

=\frac{1}{a(n+1)}\left\{x+\sqrt{1+x^2}\right\}^{n+1}+\frac{1}{-b(n-1)}\left\{x+\sqrt{1+x^2}\right\}^{n-1}+C

Then

(a+b)

is equal to

View answer and explanation

Correct option: C

Option C is correct because after evaluating the integral and comparing coefficients, the value of (a+b) is found to be 4.

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