JEE PHYSICS MCQ: GRAVITATION

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A particle of mass

m

is dropped from a great height

h

above the hole in the earth dug along its diameter. Then, which of the following statement is correct?

View answer and explanation

Correct option: D

The speed of the particle at the centre of earth equals

\sqrt{\frac{G M(R+3 h)}{R(R+h)}}

, where

R

and

M

are the radius and mass of the earth, respectively.

Option D is correct because it accurately calculates the particle's speed at the Earth's center considering its initial height and the varying gravitational force inside the Earth.

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The escape velocity for a body projected vertically upwards from the surface of the earth is

11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

. If the body is projected in a direction making an angle of

{45^0}

with the vertical, the escape velocity will be The escape velocity of a body projected from the surface of earth is

v_e

. If the body is projected at an angle

\theta

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