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JEE PHYSICS MCQ: OSCILLATIONS

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A particle executes simple harmonic motion between xx =−A  and  x=+A= - A\,\,\mathrm{and}\,\,x = + A The time taken for it to go from 0to  A/2  is  T10\mathrm{ }to\;A/2\,\,is\,\,{T_1} and to go from A/2A/2 to A  is  T2A\,\,\mathrm{is}\,\,{T_2} Then
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Correct option: A
T1<T2{T_1} < {T_2}
Option A (T1<T2{T_1} < {T_2}) is correct because in SHM, the particle's speed is higher near the equilibrium position (x=0) and lower near the extreme positions (x=A).

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