${\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3} + {\rm{Fe}}{\left( {{\rm{OH}}} \right)_2}$

${\rm{FeO}} + {\rm{Fe}}{({\rm{OH}})_2}$

${\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3}$

${\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3}{\kern 1pt} {\kern 1pt} {\rm{and }}{\kern 1pt} {\kern 1pt} {\rm{Fe}}{\left( {{\rm{OH}}} \right)_3}$

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Rust is

View answer and explanation

Correct option: C

\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} + \mathrm{Fe}{\left( {\mathrm{OH}} \right)_2}

Option C (

\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} + \mathrm{Fe}{\left( {\mathrm{OH}} \right)_2}

) is correct because rust is a mixture of iron oxide and iron hydroxide.

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