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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A particle starts from the origin of coordinates at time t=0 and moves in the x-y plane with a constant acceleration α\alpha in the y-diretion. Its equation of motion is y=βx2y = \mathrm{\beta }{x^2}. Its velocity component in the x-direction is
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Correct option: D
α2β\sqrt {\frac{\mathrm{\alpha }}{{2\mathrm{\beta }}}}
Option D (α2β\sqrt {\frac{{\alpha }}{{2\mathrm{\beta }}}}) is correct because the velocity component in the x-direction is constant and can be derived from the given equations of motion.

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