JEE MATHEMATICS MCQ: RELATIONS

1 Easy

1 of 1

Application +4 | -1

f:R \to R

is defined by

f\left( x \right) = {x^2} - 6x - 14

, then

{f^{ - 1}}\left( 2 \right)

equals to

View answer and explanation

Correct option: D

\left\{ \phi \right\}

Option D (

\{\phi\}

) is correct because the function is not one-to-one, and thus does not have a well-defined inverse at x=2.

More Questions from RELATIONS

Practice All Chapter MCQs →

\mathrm{Z}

R

\mathrm{N}

\mathrm{R}

\mathrm{N} \times \mathrm{N}

(\mathrm{a}, \mathrm{b}) \mathrm{R}(\mathrm{c}, \mathrm{d})

a d(b+c)=b c(a+d)

\mathrm{R}

W

R

R=\{(x, y) \in W \times W \mid

x

y

\}

S

R = \{ \left( {a,\;b} \right):1 + ab > 0\}

S

X

R

X

A

B

R

R

N

R = \left\{ {\left( {x,\;y} \right):4x + 3y = 20} \right\}

R