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NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Consider the following electrochemical cell at 298 K298 \mathrm{~K}

Ag(s)∣AgI(s)∥I−(aq)∥Cl−(aq)∣∣Hg2Cl2∣Hg(l)Pt(s)[Given ECl−∣Hg2Cl2∣Hg0=0.26 V⋅EAg+/Ag0=0.8 V,Ksp(AgI)=10−16 and 2.303RTF=0.06]\begin{aligned} & {Ag}(s)\left|A g I(s)\left\|I^{-}(a q)\right\| Cl^{-}(a q)\right|\left|H g_2 Cl_2\right| H g(l) P t(s) \\ & {\left[\text {Given } E_{{Cl}^{-}\left|{Hg}_2 {C} l_2\right| {Hg}}^0=0.26 {~V} \cdot E_{{Ag}^{+} / {Ag}}^0=0.8 {~V}, K_{s p}({AgI})=10^{-16} \text { and } \frac{2.303 R T}{F}=0.06\right]} \\ \end{aligned}

The overall reaction occurring in the above all is
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Correct option: A
12Hg2Cl2(s)+Ag(s)+I−(aq)→Hg(l)+Cl−(aq)+AgI(s)\frac{1}{2} {Hg}_2 {Cl}_2(s)+{Ag}(s)+{I}^{-}({aq}) \rightarrow {Hg}(l)+{Cl}^{-}({aq})+{AgI}(s)
Option A is correct because it represents the overall cell reaction based on the given cell notation and the standard reduction potentials.

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