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JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1
Temperature of 100gm100 \mathrm{gm} water is changed from 0∘C0^{\circ} \mathrm{C} to 3∘C3^{\circ} \mathrm{C} in this process, heat supplied to water will be (specified heat of water =1 cal g−1∘C−1=1 \mathrm{~cal} \mathrm{~g}^{-1}{ }^{\circ} \mathrm{C}^{-1}
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Correct option: C
less than 300 cal300 \mathrm{~cal}
Option C (less than 300 cal300 \mathrm{~cal}) is correct because the density of water increases from 0∘C0^{\circ} \mathrm{C} to 4∘C4^{\circ} \mathrm{C}, resulting in negative work done by the system.

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