JEE MATHEMATICS MCQ: TRANSFORMATION OF AXES

1 Easy

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Application +4 | -1

Without change of axes the origin is shifted to

\left( {h,\;k} \right)

, then from the equation

{x^2} + {y^2} - 4x + 6y - 7 = 0

the terms containing linear powers are missing. The point

\left( {h,\;k} \right)

View answer and explanation

Correct option: C

\left( {2, - 3} \right)

Option C ((2, -3)) is correct because shifting the origin to this point eliminates the linear terms in the equation.

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