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JEE MATHEMATICS MCQ: TRANSFORMATION OF AXES

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Application +4 | -1
The coordinates of the point where origin should be shifted so that the equation y2+4y+8x−2=0y^2+4 y+8 x-2=0 will not contain term in yy and the constant term, are
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Correct option: A
(34,−2)\left(\frac{3}{4},-2\right)
Option A (3/4, -2) is correct because by shifting the origin to this point, the y term and the constant term vanish in the transformed equation.

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