JEE MATHEMATICS MCQ: FUNCTIONS

1 Hard

1 of 1

Analyzing +4 | -1

Let

x = \left[ {\frac{{a + 2b}}{{a + b}}} \right]

and

y = \frac{a}{b}

, where

a

and

b

are positive integers. If

{y^2} > 2

then

View answer and explanation

Correct option: B

{x^2} < 2

Option B (

{x^2} < 2

) is correct because given the conditions, the value of x is such that its square is less than 2.

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