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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy
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Application +4 | -1
If sin⁡  x+sin⁡2x=1\sin \,\,x + {\sin ^2}x = 1, then value of cos⁡2 x+cos⁡4x{\cos ^2}\,x + {\cos ^4}x is
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Correct option: A
1\mathrm{1}
Option A (1) is correct because given sin⁡ x+sin⁡2x=1\sin \,x + {\sin ^2}x = 1, we can deduce that sin⁡x=cos⁡2x\sin x = {\cos ^2}x, and substituting this into cos⁡2 x+cos⁡4x{\cos ^2}\,x + {\cos ^4}x gives us 1.

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