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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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If α+β−γ=π\alpha+\beta-\gamma=\pi, then sin⁡2α+sin⁡2β−sin⁡2γ=\sin ^2 \alpha+\sin ^2 \beta-\sin ^2 \gamma=
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Correct option: C
2sin⁡αsin⁡βcos⁡γ2 \sin \alpha \sin \beta \cos \gamma
Option A (2sin⁡αsin⁡βcos⁡γ2 \sin \alpha \sin \beta \cos \gamma) is correct because by using trigonometric identities and the given condition α+β−γ=π\alpha + \beta - \gamma = \pi, the expression simplifies to 2sin⁡αsin⁡βcos⁡γ2 \sin \alpha \sin \beta \cos \gamma.

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