JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

The smallest positive integer

n

for which

\left(\frac{1+i}{1-i}\right)^n=-1

View answer and explanation

Correct option: B

Option B (2) is correct because when n=2, ((1+i)/(1-i))^n simplifies to -1, satisfying the given condition.

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

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