JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

S = \left\{ {z \in C:\arg \left( {\frac{{z - 2}}{{z + 2}}} \right) = \frac{\pi }{3}} \right\}

, then

S

View answer and explanation

Correct option: C

A circle

The correct answer is C (A circle) because the given condition represents a circle in the complex plane.

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

\gamma

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