The first and second dissociation constants of an acid ${{\rm{H}}_2}A\,{\rm{are}}\,\,1.0 \times {10^{ - 5}}\,{\rm{and}}\,\,5.0 \times {10^{ - 10}}$ respectively. The overall dissociation constant of the acid will be

NEET UG CHEMISTRY MCQ: Equilibrium

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The first and second dissociation constants of an acid

{\mathrm{H}_2}A\,\mathrm{are}\,\,1.0 \times {10^{ - 5}}\,\mathrm{and}\,\,5.0 \times {10^{ - 10}}

respectively. The overall dissociation constant of the acid will be

View answer and explanation

Correct option: C

5.0 \times {10^{ - 15}}

Option C (

5.0 \times {10^{ - 15}}

) is correct because the overall dissociation constant is the product of the individual dissociation constants.

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}