$\smallint \,(1 - \cos \,\,x)\;\,{\rm{cose}}{{\rm{c}}^2}\,\,dx$ is equal to

$ - \,\,\cot \,\,\frac{x}{2}\,\, + \,\,c$

$2\,\,\tan \,\,\frac{x}{2}\,\, + \,\,c$

$ - \,2\,\,\cot \,\,\frac{x}{2}\,\, + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \,(1 - \cos \,\,x)\;\,\mathrm{cose}{\mathrm{c}^2}\,\,dx

is equal to

View answer and explanation

Correct option: A

\tan \,\,\frac{x}{2}\,\, + \,\,c

Option A (

\tan \frac{x}{2}\\ + \\ c

) is correct because the integral simplifies to

\int \frac{1}{{1 + \cos x}} dx

, which evaluates to

\tan \frac{x}{2}\\ + \\ c