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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1
cos⁡2A2+cos⁡2B2+cos⁡2C2=\cos ^2 \frac{A}{2}+\cos ^2 \frac{B}{2}+\cos ^2 \frac{C}{2}=
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Correct option: B
2+2sin⁡A2sin⁡B2sin⁡C22+2 \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2}
Option B (2+2sin⁡A2sin⁡B2sin⁡C22+2 \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2}) is correct because by applying half-angle formulas and trigonometric identities, the expression simplifies to the given form.

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