$\smallint \,\frac{{{x^2}}}{{1\,\, + \,\,{x^6}}}\,dx$ is equal to

$\log \,\,\left( {1 + {x^3}} \right) + c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \,\frac{{{x^2}}}{{1\,\, + \,\,{x^6}}}\,dx

is equal to

View answer and explanation

Correct option: B

\frac{1}{3}\,\,{\tan ^{ - 1}}\left( {{x^3}} \right) + c

Option B (

\frac{1}{3}\\ {\tan ^{ - 1}}\left( {{x^3}} \right) + c

) is correct because by substituting

t = x^3

, the integral simplifies to a standard arctangent integral.

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