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JEE MATHEMATICS MCQ: FUNCTIONS

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Let f(x)=x,g(x)=1xf(x)=x, g(x)=\frac{1}{x} and h(x)=f(x)⋅g(x)h(x)=f(x) \cdot g(x), then h(x)=1h(x)=1
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Correct option: D
∀x∈R,x≠0\forall x \in R, x \neq 0
Option D (∀x∈R,x≠0\forall x \in R, x \neq 0) is correct because h(x)=f(x)⋅g(x)=x⋅1x=1h(x) = f(x) \cdot g(x) = x \cdot \frac{{1}}{{x}} = 1 only when xx is a real number not equal to 0, as g(x)g(x) is undefined at x=0x=0.

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