In an isobaric process, $\Delta Q=\frac{\gamma K}{\gamma-1}$, where $\gamma$ is $\boldsymbol{C}_{\boldsymbol{p}} / \boldsymbol{C}_{\boldsymbol{v}}$ What is $K$ ?

JEE PHYSICS MCQ: THERMODYNAMICS

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In an isobaric process,

\Delta Q=\frac{\gamma K}{\gamma-1}

, where

\gamma

\boldsymbol{C}_{\boldsymbol{p}} / \boldsymbol{C}_{\boldsymbol{v}}

What is

K

View answer and explanation

Correct option: D

Work done

Option D is correct because in an isobaric process, the heat added is related to the change in internal energy and the work done, and K represents the work done.

JEE PHYSICS MCQ: THERMODYNAMICS

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