JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Analyzing +4 | -1

I=\int e^x\left(\tan ^{-1} x+\frac{2 x}{\left(1+x^2\right)^2}\right) d x

then

I

is equal to

View answer and explanation

Correct option: A

e^x\left(\tan ^{-1} x-\frac{1}{1+x^2}\right)+c

The correct answer is

e^x(\tan ^{-1} x-\frac{1}{1+x^2})+c

because it fits the form of the integral

\int e^x(f(x)+f'(x))dx = e^x f(x) + c

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