The value of $\smallint \,\,\frac{{{x^2} + 1}}{{{x^2} - 1}}\,\,dx$ is

$\log \,\,\left( {{x^2} - 1} \right) + c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

The value of

\int \,\,\frac{{{x^2} + 1}}{{{x^2} - 1}}\,\,dx

View answer and explanation

Correct option: C

x + \log \,\,\left( {\frac{{x - 1}}{{x + 1}}} \right) + c

Option C (

x + \log \,\left( {\frac{{x - 1}}{{x + 1}}} \right) + c

) is correct because after performing the integration, the result matches this expression.

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