JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

Let

z=\cos \theta+i \sin \theta

, where

i=\sqrt{-1}

. Then the value of

\sum\limits_{m=1}^{15} \operatorname{Im}\left(z^{2 m-1}\right)

\theta=2^{\circ}

View answer and explanation

Correct option: D

\frac{1}{4 \sin 2^{\circ}}

Option D (

\frac{{1}}{{4 \sin 2^{\circ}}}

) is correct because the sum of the imaginary parts simplifies to this expression using trigonometric identities.

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

\gamma

|\alpha-\beta|

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z \in C

2x = - 1 + \sqrt 3 i

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