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JEE PHYSICS MCQ: OSCILLATIONS

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The displacement of a particle (in meter) from its mean position is given by the equation y=0.2(cos⁡2πt2−sin⁡2πt2)y=0.2\left(\cos ^2 \frac{\pi t}{2}-\sin ^2 \frac{\pi t}{2}\right). The motion of the above particle is
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Correct option: B
simple harmonic with amplitude 0.2 m0.2 \mathrm{~m}
Option B (simple harmonic with amplitude 0.2 m0.2 \mathrm{~m}) is correct because the given equation can be simplified to a standard SHM equation with an amplitude of 0.2 m.

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